Nilai lim_(x→-2)⁡ ((x+6) sin⁡(x+2))/(x^2-3x-10)=⋯

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Bahas Soal Matematika   »   Limit   ›  

Nilai \( \displaystyle \lim_{x \to -2} \ \frac{(x+6) \sin (x+2)}{x^2-3x-10} = \cdots \)

  1. -4/3
  2. -4/7
  3. -2/5
  4. 0
  5. 1

(UN SMA IPA 2004)

Pembahasan:

\begin{aligned} \lim_{x \to -2} \ \frac{(x+6) \sin (x+2)}{x^2-3x-10} &= \lim_{x \to -2} \ \frac{(x+6) \sin (x+2)}{(x-5)(x+2)} \\[8pt] &= \lim_{x \to -2} \ \frac{(x+6)}{(x-5)} \cdot \lim_{x \to -2} \ \frac{\sin (x+2)}{(x+2)} \\[8pt] &= \frac{-2+6}{-2-5} \cdot 1 \\[8pt] &= -\frac{4}{7} \end{aligned}

Jawaban B.